Web x2 + 18x + 81 = 0 x 2 + 18 x + 81 = 0 factor using the perfect square rule. As 81 is the square of 9 and middle term 18 is double of this number, (compare it with (x + a)2 = x2 + 2ax +a2) hence x2 +18x + 81 is a complete square. 18x = 2⋅ x⋅9 18 x = 2 ⋅ x ⋅ 9 rewrite the polynomial. Web factor x^2+18x+81 x2 + 18x + 81 x 2 + 18 x + 81 rewrite 81 81 as 92 9 2. X2 + 18x+92 x 2 + 18 x + 9 2 check that the middle term is two times the product of the numbers being squared in the first term and third term. (x+9)2 = 0 ( x + 9) 2 = 0 set the x+9 x + 9 equal to 0 0. X+9 = 0 x + 9 = 0 subtract 9 9 from both sides of the equation. Web how do you factor x2 + 18x + 81? A = 1 a = 1 h = 9 h = 9 k = 0 k = 0 find the vertex (h,k) ( h, k). Step 1 :trying to factor by splitting the middle term 1.1 factoring x2+18x+81 the first term is, x2.
Web factor x^2+18x+81 x2 + 18x + 81 x 2 + 18 x + 81 rewrite 81 81 as 92 9 2. As 81 is the square of 9 and middle term 18 is double of this number, (compare it with (x + a)2 = x2 + 2ax +a2) hence x2 +18x + 81 is a complete square. A = 1 a = 1 h = 9 h = 9 k = 0 k = 0 find the vertex (h,k) ( h, k). Algebra polynomials and factoring factoring completely 1 answer shwetank mauria jun 1, 2016 x2 +18x +81 = (x + 9)2 explanation: X2 + 2⋅x⋅9+92 x 2 + 2 ⋅ x ⋅ 9 + 9 2 18x = 2⋅ x⋅9 18 x = 2 ⋅ x ⋅ 9 rewrite the polynomial. Web how do you factor x2 + 18x + 81? Step 1 :trying to factor by splitting the middle term 1.1 factoring x2+18x+81 the first term is, x2. Web x2+18x+81=0 one solution was found : (x+9)2 = 0 ( x + 9) 2 = 0 set the x+9 x + 9 equal to 0 0. Web factor x^2+18x+81 x2 + 18x + 81 x 2 + 18 x + 81 rewrite 81 81 as 92 9 2.
