Web how do you solve 2x2 +3x+ 5 = 0 using the quadratic formula? Web 3x2+3x+5=0 two solutions were found : A the equation has real roots. Web use the result from part c to find the two solutions to the equation 2x 2 ?3x?5=0. With either (|a|,|b|) = (1,5),(5,1) by inspection we see a = 5,b = −1, therefore we have: Factor the equation, note that both 2 and 5 are prime numbers, therefore they can only have themselves and 1 as a factor. The discriminant is given by: Roots are imaginary in the. Step 1 :equation at the end of step 1 : Nature of the roots = ?
Δ = b2 − 4 ⋅ a ⋅ c. Step 1 :equation at the end of step 1 : The solutions are found using the formula. Web if the real roots exist, find them: 2x2 − 3x −5 = (2x − a)(x − b) = 0. The equation is of the form ax2 + bx + c = 0 where: C data insufficient d none of these easy solution verified by toppr correct option is b) here the quadratic equation is 2x 2−3x+5=0 comparing it with ax 2+bx+c=0, we get a=2,b=−3,c=5 therefore, discriminant, d=b 2−4ac (−3) 2−4×2×5 =9−40 Ex 4.4, 1 (ii) important → ask a doubt (live) Step 1 :equation at the end of step. The discriminant is given by: Step 1 :equation at the end of step 1 :
